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Limits and Their Properties

1.5 Infinite Limits

Focus on compare infinite one-sided limits, signed infinite limits, vertical asymptotes versus holes, squared denominators.

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Ideas in this lesson

Idea 1 of 4

Compare infinite one-sided limits

Opposite infinite one-sided limits mean the two-sided limit does not exist. A squared denominator can send both sides to positive infinity.

Worked example 1

Find the two-sided limit as x→2x \to 2 of 1(x−2)\dfrac{1}{(x - 2)}.
  1. x−2→0−  ⟹  f(x)→−∞x - 2 \to 0^{-} \implies f(x) \to -\infty
  2. x−2→0+  ⟹  f(x)→∞x - 2 \to 0^{+} \implies f(x) \to \infty
  3. lim⁡\displaystyle \lim ₓ→2−f(x)≠lim⁡\displaystyle \to 2^{-} f(x) \ne \lim ₓ→2+f(x)  ⟹  DNE\to 2^{+} f(x) \implies DNE

Answer: Does not exist

Worked example 2

Find the two-sided limit as x→3x \to 3 of 1(x−3)2\dfrac{1}{(x - 3)^{2}}.
  1. x−3→0−  ⟹  f(x)→∞x - 3 \to 0^{-} \implies f(x) \to \infty
  2. x−3→0+  ⟹  f(x)→∞x - 3 \to 0^{+} \implies f(x) \to \infty
  3. lim⁡f(x)=∞\displaystyle \lim f(x) = \infty

Answer: Positive infinity

Idea 2 of 4

Signed infinite limits

Approaching a zero denominator requires a sign check. A reciprocal may grow toward positive or negative infinity.

Worked example 1

Evaluate lim⁡x→2+1x−2\displaystyle \lim\limits_{x\to 2^{+}} \dfrac{1}{x - 2}.
  1. x>2  ⟹  x−2>0x > 2 \implies x - 2 > 0
  2. x−2→0+x - 2 \to 0^{+}
  3. Reciprocal limit =∞= \infty

Answer: ∞\infty

Worked example 2

Evaluate lim⁡x→3−1x−3\displaystyle \lim\limits_{x\to 3^{-}} \dfrac{1}{x - 3}.
  1. x<3  ⟹  x−3<0x < 3 \implies x - 3 < 0
  2. x−3→0−x - 3 \to 0^{-}
  3. Reciprocal limit =−∞= -\infty

Answer: −∞-\infty

Idea 3 of 4

Vertical asymptotes versus holes

Cancel common factors only away from excluded inputs. Remaining denominator zeros may produce asymptotes; canceled zeros may produce holes.

Worked example 1

Find the vertical asymptote of f(x)=1x−2f(x) = \dfrac{1}{x - 2}.
  1. x−2=0  ⟹  x=2x - 2 = 0 \implies x = 2
  2. Numerator at x=2x = 2 is 1≠01 \ne 0
  3. Vertical asymptote: x=2x = 2

Answer: 22

Worked example 2

Find the vertical asymptote of f(x)=x+1x−3f(x) = \dfrac{x + 1}{x - 3}.
  1. x−3=0  ⟹  x=3x - 3 = 0 \implies x = 3
  2. Numerator at x=3x = 3 is 4≠04 \ne 0
  3. Vertical asymptote: x=3x = 3

Answer: 33

Idea 4 of 4

Squared denominators

A squared nonzero denominator is positive on either side. This can make both one-sided limits grow in the same direction.

Worked example 1

Evaluate lim⁡x→2+1x−2\displaystyle \lim\limits_{x\to 2^{+}} \dfrac{1}{x - 2}.
  1. x>2  ⟹  x−2>0x > 2 \implies x - 2 > 0
  2. x−2→0+x - 2 \to 0^{+}
  3. Reciprocal limit =∞= \infty

Answer: ∞\infty

Worked example 2

Evaluate lim⁡x→3−1x−3\displaystyle \lim\limits_{x\to 3^{-}} \dfrac{1}{x - 3}.
  1. x<3  ⟹  x−3<0x < 3 \implies x - 3 < 0
  2. x−3→0−x - 3 \to 0^{-}
  3. Reciprocal limit =−∞= -\infty

Answer: −∞-\infty

Resource alignment: Larson & Edwards, Calculus of a Single Variable, Tenth Edition, §1.5,p1.5, p. 8383. Explanations, diagrams and numerical practice variants are original MathLab content aligned to this section.