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Applications of Differentiation

3.3 Increasing and Decreasing Functions and the First Derivative Test

Focus on increasing and decreasing intervals, first derivative test, critical-point classification.

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Ideas in this lesson

Idea 1 of 3

Increasing and decreasing intervals

The sign of f′f' describes monotonicity on an interval. Split the number line at all relevant critical inputs.

Worked example 1

For f(x)=(x−2)2f(x) = (x - 2)^{2}, where is ff decreasing?
  1. f′(x)=2(x−2)f'(x) = 2(x - 2)
  2. x<2  ⟹  f′(x)<0x < 2 \implies f'(x) < 0; x>2  ⟹  f′(x)>0x > 2 \implies f'(x) > 0
  3. Requested interval/point: (−∞,2)(-\infty , 2)

Answer: (−∞,2)(-\infty , 2)

Worked example 2

For f(x)=(x−3)2f(x) = (x - 3)^{2}, where is ff increasing?
  1. f′(x)=2(x−3)f'(x) = 2(x - 3)
  2. x<3  ⟹  f′(x)<0x < 3 \implies f'(x) < 0; x>3  ⟹  f′(x)>0x > 3 \implies f'(x) > 0
  3. Requested interval/point: (3,∞)(3, \infty )

Answer: (3,∞)(3, \infty )

Idea 2 of 3

First Derivative Test

A positive-to-negative derivative sign change gives a maximum; negative-to-positive gives a minimum.

Worked example 1

For f(x)=x3−12xf(x) = x^{3} - 12x, find the positive critical number.
Coordinate graph-3-2-1123-20-101020xy
  1. f′(x)=3(x−2)(x+2)=0  ⟹  x=±2f'(x) = 3(x - 2)(x + 2) = 0 \implies x = \pm 2
  2. f′(x)>0f'(x) > 0 on (−∞,−2)(-\infty , -2) and (2,∞)(2, \infty ); f′(x)<0f'(x) < 0 on (−2,2)(-2, 2)
  3. xx−2-222
    f(x)f(x)1616−16-16
    requested value =2= 2

Answer: 22

Worked example 2

For f(x)=x3−27xf(x) = x^{3} - 27x, find the local minimum value.
Coordinate graph-4-3-2-11234-80-60-40-2020406080xy
  1. f′(x)=3(x−3)(x+3)=0  ⟹  x=±3f'(x) = 3(x - 3)(x + 3) = 0 \implies x = \pm 3
  2. f′(x)>0f'(x) > 0 on (−∞,−3)(-\infty , -3) and (3,∞)(3, \infty ); f′(x)<0f'(x) < 0 on (−3,3)(-3, 3)
  3. xx−3-333
    f(x)f(x)5454−54-54
    requested value =−54= -54

Answer: −54-54

Idea 3 of 3

Critical-point classification

A zero derivative alone is insufficient. Inspect the sign on both sides.

Worked example 1

For f(x)=(x−2)2f(x) = (x - 2)^{2}, where is ff decreasing?
  1. f′(x)=2(x−2)f'(x) = 2(x - 2)
  2. x<2  ⟹  f′(x)<0x < 2 \implies f'(x) < 0; x>2  ⟹  f′(x)>0x > 2 \implies f'(x) > 0
  3. Requested interval/point: (−∞,2)(-\infty , 2)

Answer: (−∞,2)(-\infty , 2)

Worked example 2

For f(x)=(x−3)2f(x) = (x - 3)^{2}, where is ff increasing?
  1. f′(x)=2(x−3)f'(x) = 2(x - 3)
  2. x<3  ⟹  f′(x)<0x < 3 \implies f'(x) < 0; x>3  ⟹  f′(x)>0x > 3 \implies f'(x) > 0
  3. Requested interval/point: (3,∞)(3, \infty )

Answer: (3,∞)(3, \infty )

Resource alignment: Larson & Edwards, Calculus of a Single Variable, Tenth Edition, §3.3,p3.3, p. 177177. Explanations, diagrams and numerical practice variants are original MathLab content aligned to this section.