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3.7 Polynomial and Rational Inequalities

Focus on sign of factored product and exclude denominator zero.

Before you solve

Ideas in this lesson

Explore the lesson brief and the worked example for Idea 11. Create a free account to continue with the remaining ideas and practice.

Lesson brief and rules

3.7 Polynomial and Rational Inequalities

Find critical values, then test the sign on each interval; exclude undefined inputs.

Worked example 11
01 / Move all terms to one side and solve 2x3−x2−4x+6≥3x2 x^{3} - x^{2} - 4 x + 6\ge3 x. Factor completely over the reals and show a sign table. Complete the written work or drawing first. The selected answer checks the result only; your reasoning or drawing needs teacher/self-review.
02 / numerator factor x−1x - 1, signs from left to right: negative, negative, positive, positive.
03 / numerator factor x+2x + 2, signs from left to right: negative, positive, positive, positive.
04 / numerator factor 2x−32 x - 3, signs from left to right: negative, negative, negative, positive.
05 / With zero on the right, factor the expression as (x−1)(x+2)(2x−3)\left(x - 1\right) \left(x + 2\right) \left(2 x - 3\right).
06 / Cut points: −2-2, 11, 32\dfrac{3}{2}. Original excluded inputs: none.
07 / Sign chart: between −∞-\infty and −2-2: negative; between −2-2 and 11: positive; between 11 and 32\dfrac{3}{2}: negative; between 32\dfrac{3}{2} and ∞\infty: positive.
08 / Include numerator zeros that are in the original domain; never include denominator zeros.
09 / The solution is [−2,1]∪[32,∞)\left[-2, 1\right] \cup \left[\dfrac{3}{2}, \infty\right).
Worked example 2 · Solve factored and expanded polynomial inequalities

Move all terms to one side and solve x4−x3−13x2+5x+12<4xx^{4} - x^{3} - 13 x^{2} + 5 x + 12<4 x. Factor completely over the reals and show a sign table. Complete the written work or drawing first. The selected answer checks the result only; your reasoning or drawing needs teacher/self-review.

numerator factor x−4x - 4, signs from left to right: negative, negative, negative, negative, positive.
numerator factor x−1x - 1, signs from left to right: negative, negative, negative, positive, positive.
numerator factor x+1x + 1, signs from left to right: negative, negative, positive, positive, positive.
numerator factor x+3x + 3, signs from left to right: negative, positive, positive, positive, positive.
With zero on the right, factor the expression as (x−4)(x−1)(x+1)(x+3)\left(x - 4\right) \left(x - 1\right) \left(x + 1\right) \left(x + 3\right).
Cut points: −3-3, −1-1, 11, 44. Original excluded inputs: none.
Sign chart: between −∞-\infty and −3-3: positive; between −3-3 and −1-1: negative; between −1-1 and 11: positive; between 11 and 44: negative; between 44 and ∞\infty: positive.
Use open endpoints at zeros because the comparison is strict; poles are always excluded.
The solution is (−3,−1)∪(1,4)\left(-3, -1\right) \cup \left(1, 4\right).
Written-work review:

15 questions with a worked answer for each.Start practice ↗
Textbook reference: Stewart, Redlin & Watson, Precalculus: Mathematics for Calculus, 7th ed. (Cengage, 2016). The explanations and practice here are original, organized by textbook section.