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Use inverse operations: logb(bx)=x and blogbx=x for x>0.
Worked example 1
01 / Define an exponential equation and explain the general solution procedure. Solve 42x−1=64. Give every real solution exactly and to six decimal places when needed, and check the original equation. Written work is required; selecting an answer alone is not a complete response. Complete the written work or drawing first. The selected answer checks the result only; your reasoning or drawing needs teacher/self-review.
02 / An exponential equation has the unknown in an exponent. First isolate or normalize the exponential; then use same-base injectivity or take logarithms of positive sides, solve and check.
03 / Rewrite the right side as 43.
04 / Since this exponential has a positive base unequal to one, it is one-to-one. Hence 2x−1=3.
05 / Solve to get x=2. Substitution gives the same cube on each side.
06 / The solution is x=2≈2.000000. These decimals are rounded to six places; the preceding logarithmic values are exact.
Worked example 2 · Solve same-base and isolated exponential equations
Solve 3x2=3(3)x−2. Give every real solution exactly and to six decimal places when needed, and check the original equation. Written work is required; selecting an answer alone is not a complete response. Complete the written work or drawing first. The selected answer checks the result only; your reasoning or drawing needs teacher/self-review.
Equate exponents by injectivity: x2−3x+2 equals zero. Factor: (x−1)(x−2)=0. Both roots 1, 2 are valid because exponentials have all-real input domain. At each root the two exponents agree; the original sides therefore agree. The solutions are x=1≈1.000000, x=2≈2.000000. These decimals are rounded to six places; the preceding logarithmic values are exact. Written-work review:
Accept mathematically equivalent derivations and valid alternative counterexamples. Every requested conclusion, original-domain restriction, justification, precision and unit requirement still applies; the listed solution is one acceptable route.
Required written evidence: Equate exponents by injectivity: x2−3x+2 equals zero.
Required written evidence: Factor: (x−1)(x−2)=0.
Required written evidence: Both roots 1, 2 are valid because exponentials have all-real input domain.
Required written evidence: At each root the two exponents agree; the original sides therefore agree.
Required written evidence: The solutions are x=1≈1.000000, x=2≈2.000000. These decimals are rounded to six places; the preceding logarithmic values are exact.
Textbook reference: Stewart, Redlin & Watson, Precalculus: Mathematics for Calculus, 7th ed. (Cengage, 2016). The explanations and practice here are original, organized by textbook section.