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4.6 Modeling with Exponential Functions

Focus on exponential growth and decay model.

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Ideas in this lesson

Explore the lesson brief and the worked example for Idea 11. Create a free account to continue with the remaining ideas and practice.

Lesson brief and rules

4.6 Modeling with Exponential Functions

In A(t)=A0bt,A0A(t)=A_{0}b^{t}, A_{0} is initial value and bb is the per-period factor.

Worked example 11
01 / A simulated culture begins with 240240 organisms and doubles every 3030 minutes. With tt measured in hours, derive its base −2-2 and base −e-e models, calculate the count at 1.251.25 hours, solve the time to 12001200 organisms, and plot the model through that target. Explain the difference between a continuous estimated count and an actual integer count. Show written work; selecting a summary alone is not a complete response. Complete the written work or drawing first. The selected answer checks the result only; your reasoning or drawing needs teacher/self-review.
02 / One doubling takes 3030 minutes, or a=3060=0.5a=\dfrac{30}{60}=0.5 hours. After tt hours the number of doubling periods is ta\dfrac{t}{a}.
03 / N0=240N_0=240.
04 / N(t)=N0 2ta=N0e(ln⁡2)taN(t)=N_0\,2^{\dfrac{t}{a}}=N_0 e^{(\ln 2)\dfrac{t}{a}}. Thus r=ln⁡20.5r=\dfrac{\ln 2}{0.5}≈1.386294\approx 1.386294 per hour. The base −e-e and base −2-2 graphs coincide exactly when the unrounded rate is used.
05 / N(1.25)=N0 21.250.5≈1357.65N(1.25)=N_0\,2^{\dfrac{1.25}{0.5}}\approx 1357.65 organisms; round only the final estimated count to 13581358.
06 / N0ert=1200⇒rt=ln⁡(1200N0)⇒t=ln⁡(1200N0)r≈1.161N_0e^{rt}=1200\Rightarrow rt=\ln\left(\dfrac{1200}{N_0}\right)\Rightarrow t=\dfrac{\ln(\dfrac{1200}{N_0})}{r}\approx 1.161 hours from introduction.
07 / Physical domain: t≥0t\ge0. The continuous curve estimates an integer population and assumes an unchanged doubling time and no resource limit. It does not assert a fractional organism or indefinite real-world growth.
08 /
000.31367.350.62734.70.941102.061.251469.41Hours since introductionOrganisms
Reference graph. Open circles: observations or key values. Solid: both equivalent models.
Worked example 2 · Model doubling, recover initial counts and convert bases

A simulated colony was introduced 3.753.75 hours ago and now has an estimated 16251625 organisms. Its doubling time is 4545 minutes. Take t=0t=0 at introduction. Recover the initial count without early rounding, write equivalent base −2-2 and base −e-e models with time in hours, predict the count 11 hours from now, find when the count reaches 4062.54062.5, and sketch the model from introduction through that target. Show written work; selecting a summary alone is not a complete response. Complete the written work or drawing first. The selected answer checks the result only; your reasoning or drawing needs teacher/self-review.

One doubling takes 4545 minutes, or a=4560=0.75a=\dfrac{45}{60}=0.75 hours. After tt hours the number of doubling periods is ta\dfrac{t}{a}.
N0=162523.750.75≈50.78125N_0=\dfrac{1625}{2^{\dfrac{3.75}{0.75}}}\approx 50.78125 organisms. Retain this exact expression in later work.
N(t)=N0 2ta=N0e(ln⁡2)taN(t)=N_0\,2^{\dfrac{t}{a}}=N_0 e^{(\ln 2)\dfrac{t}{a}}. Thus r=ln⁡20.75r=\dfrac{\ln 2}{0.75}≈0.924196\approx 0.924196 per hour. The base −e-e and base −2-2 graphs coincide exactly when the unrounded rate is used.
N(4.75)=N0 24.750.75≈4094.74N(4.75)=N_0\,2^{\dfrac{4.75}{0.75}}\approx 4094.74 organisms; round only the final estimated count to 40954095.
N0ert=4062.5⇒rt=ln⁡(4062.5N0)⇒t=ln⁡(4062.5N0)r≈4.7414N_0e^{rt}=4062.5\Rightarrow rt=\ln\left(\dfrac{4062.5}{N_0}\right)\Rightarrow t=\dfrac{\ln(\dfrac{4062.5}{N_0})}{r}\approx 4.7414 hours from introduction.
Physical domain: t≥0t\ge0. The continuous curve estimates an integer population and assumes an unchanged doubling time and no resource limit. It does not assert a fractional organism or indefinite real-world growth.

0−353.611.19859.572.382072.763.563285.954.754499.14Hours since introductionOrganisms
Reference graph. Open circles: observations or key values. Solid: both equivalent models.

Written-work review:

15 questions with a worked answer for each.Start practice ↗
Textbook reference: Stewart, Redlin & Watson, Precalculus: Mathematics for Calculus, 7th ed. (Cengage, 2016). The explanations and practice here are original, organized by textbook section.